I’m trying to make selenium click Button1 but for some reasons, I get the following error: selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: Button1 I believe the error is happening because it is inside a div/ul/li tag but I can’t either figure out how to do it, I’m stuck. HTML: Python Code: Edit: I found out that the html is generated
Tag: html
flask.cli.NoAppException: Could not import “app”
My application’s name is app.py, and it’s in a folder named ToDo-App, and within this folder there is another folder called templates, that contains the index.html file. In the terminal: Esam@DESKTOP-73QDAD3 MINGW32 /i/web/advanced-track/1-sql_and_data_modeling_for_the_web/ToDo-App $ FLASK_APP=app.py FLASK_DEBUG=true flask run Serving Flask app “app.py” (lazy loading) Environment: production WARNING: This is a development server. Do not use it in a production deployment.
How to format dynamically generated HTML with django
I’m trying to create a sheet of labels to print out with a QR code a logo and phone number, the QR codes are generated separately from an xlsx file and they work. My issue is formatting them in the HTML. I’m not sure how to change the for loop so it creates a row for each time an image
Selenium on Python unable to locate nested class element
I’m trying to reach a nested class, originally I used xPath but it returned an empty list, so I went through the classes individually, and one of them has an issue where selenium can’t find it. Up until Price4 it works fine, but it can’t seem to find Price5 Answer So, if you want to get the text from the
Display IFrame IPython with custom auth headers
I am developing a JupyterLab Notebook and I need to embed a website for interaction with a dashboard from within the same notebook. This would be quite straight-forward using an IFrame. However, to access this website, that I launch on my public server, JWT authentication is required so I need to send an additional header with the token. Which is
Django Render List of Dictionaries to a template
I have a list of dictionaries with same key information. How can I pass this list of dictionaries to a Django template ? When trying to send this list via views file to template it fails with an error indicating that only dictionaries are allowed. Here is the code from views file Here is the html block- Answer Just pass
Better way of capturing multiple same tags?
I’m trying to create an scraper which scrapes download links, I want to use regex but that would be a nightmare for me to do, I’ve found this library which is called BeautifulSoup, I’m trying to capture the urls in the children of div class=”article-content” which is <p> tag, and this <h3> is the name of the urls,I don’t want
Get meta tag content by name, beautiful soup and python
I’m trying to get the meta data from this website(here’s the code). however I get this error. Any ideas? Answer From bs4 docs: You can’t use a keyword argument to search for HTML’s name element, because Beautiful Soup uses the name argument to contain the name of the tag itself. Instead, you can give a value to ‘name’ in the
Python, Django: how to get checked table rows into lists?
Good evening, I’m hoping someone knows an answer to my problem of getting all checked rows inside a table into a multidimensional list (after submit)? I know I can do something like this to get – for example – all the checked ids into a list: template: views.py But as mentioned, this will only get me a list of the
Can not print specifict values from an api response dictionnary (Dango)
i’m ne to Django and APIs and i’m struggling with this for days. Here’s my views.py file : And here’s the index.html : But when i try to do for example : i get an error : (TemplateSyntaxError at / Could not parse the remainder: ‘[“height”]’ from ‘t[“height”]’) Please help me and excuse me if it is a dumb question,