I have an nested list that works as [[id, price], [id, price], [id, price], [id, price]] and I need to iterate through the [0] and the [1] value to use in the request url and json data respectively. I can’t get the variable to be used in the request url but the json data seems to work fine Answer have
Tag: arrays
Get the index of the largest two values per row
For each row, I would like to get the index of the largest two values. Here’s the result I would like to obtain: Answer Use np.argsort along the second axis and take last two values reversed.
Difference of Numpy Dimension Expand code
I got confuse between two Numpy dimension expand code. First code is X[:, np.newaxis]. Second code is X[:, np.newaxis, :]. I ran this code on Jupyter, But it returns same shape and result. What is the difference? Answer Refer numpy documentation for newaxis. https://numpy.org/doc/stable/reference/constants.html#numpy.newaxis x[newaxis, :] is equivalent to x[newaxis] and x[None] Any dimension after np.newaxis is still present in
Print array value without brackets in Python
So, I have an array value like this with print(Items) it’s returning [‘*.abc.com’, ‘*.xyz.me’] but, I want to print everything without brackets like ‘*.abc.com’, ‘*.xyz.me’ Followed some way, but those are returning different not exactly what I want. Answer what about this? Output: i add a short description like mozway suggests: you convert your python list to a string (at
Scale/resize a square matrix into a larger size whilst retaining the grid structure/pattern (Python)
Like above, I want to retain the same ‘grid’ format whilst increasing the dimensions of the 2D array. How would I go about doing this? I assume the original matrix can only be scaled up by an integer n. Answer You can use numba if performance is of importance (similar post) with no python jitting and in parallel mode if
Dask Distributed: Reducing Multiple Dimensions into a Distance Matrix
I want to calculate a large distance matrix, based on a higher dimensional vector. For instance, I have 1000 instances each represented by 20 vectors of length 10. The distance between each two instances is given by the mean distance between each of the 20 vectors associated to each vector. So I want to go from a 1000 by 20
remove background of RGB image (3D array) based on another array (boolean mask)
I’m stuck on what should be fairly straight forward, but other opened questions don’t see to address exactly the same issue i’m having. I’m trying to crop an image based on boolean mask. I can do this with: (This function inputs RGB image (w, h, c) and True/False mask of shape (w, h, n) and crops a bounding box around
In Python, why my variable StartingU get updated when I only update the variable AverageU in my for loops? What is wrong with the code?
The purpose is to calculate the average value (AverageU) from a starting array (StartingU) The for loops that calculate the average values for AverageU Output: The problem is why StartingU gets updated? It should be unchanged Answer AverageU changed since this code, not after for loop. AverageU and StartingU are the same instances. You can check it with is function.
How to replace special characters(double quotes to single quotes) from a list using python so that my list become a 2D list?
from this code I got a lists will be like this. now I want to replace double quotes with the single quotes. so that this lists will become a 2D list. I tried with the given below code. but that will not help. So how can I get lists as a 2D list? Answer
Divide and Conquer to check if a value in a list is equal to its index
Given a list of distinct integers (decreasing order), return True if there is atleast position p, such that the value at position p is p. For instance, List = [4, 3, 2, 0], the function returns true since 2 is at index 2. I know we can just go for a loop and check if list[i] == i. I was