In python, I can do something like It gives me [1, 5, 99, 100, -5, -7, -100] It is sorted by positive/negative number and abs value. How can I do the same thing in R? Without splitting into positive and negative numbers? a = c(1,100,5,-5,-7,99,-100) Answer Use the order() function: Created on 2022-03-22 by the reprex package (v2.0.1) Another possibility
Tag: sorting
Why is this array changing when I’m not operating on it?
I have two arrays: And I’m running the foll)owing code: I get the following result: Why are the last elements changed? I don’t see why X is changed by indexing some elements. edit: added np.array Answer Output:
Usage of sorted with ord() and lambda in python
I was doing an exercise on Hackerrank, and in the discussion I stumbled upon a very nice one line solution to solve the following question: S is an alphanumeric string, and you have to sort it using the following rules: All sorted lowercase letters are ahead of uppercase letters. All sorted uppercase letters are ahead of digits. All sorted odd
How to use key in the sort function in this situation (Python)?
I have a list like this: Now I want to sort it, but by the number, not by the word. If I just use l.sort() it just sorts by alphabetically. My desired output should be sth like (d,0)(c,1)(a,2)(b,4) I tried l.sort(key = l[0][1]) but it won’t work too (l[0][1] actually refer to number 2, which is the second value) Answer
Sort dict by multiple keys and with int and None data in python
so I have a dict : I want to sort my dict on ‘i.chromosome’, ‘i.linkageGroup’ and ‘i.positionCm’ What I am doing : And i got : In python 2, they were doing : Could you help me please, I am lost ! Answer Given and the requirement that Nones are for int, you can solve it using where I’ve made
How can I sort a python list by key without .sort()?
I want to convert this piece of code in order to make it compatible with Numba. The only sort method that Numba support is sorted() but not with the key arg. I have to manualy sort without other lib imports or maybe just some numpy. Someone could give me an efficient way to do this sort ? Thanks Edit :
Sorting (or partially sorting) a list of objects based on a specific attribute
Problem I have a list of objects. Each object has two attributes: “score” and “coordinates”. I need to find the largest N objects of the list based on the score attribute. The main problem I’m having is sorting the objects using only the score attribute. Sorting can be partial. I’m only interested in the N largest objects. Current Solution My
How can I efficiently find distances from each value to the next lower/higher value?
I’ll tell you what structures I am using, please feel free to recommend any changes like numpy arrays or something. Anyways what I have is a list of 5 million sequential entries that correspond to a stock price. I then have 2 more lists, each of these is the same length – 5 million entries. These lists correspond to an
Python – Group(Cluster/Sort) arrays based on ranking information
I have a dataframe looks like this: I converted the dataframe into 2D arrays like this: The score of each row 1-5 actually means the people give the scores to item A, B, C, D. I would like to identify the people who have the same ranking, for example the people think A > B > C > D. And
Processing files in sorted order
I have 67 images in a directory with names as: Files are jpg files Im_260x_y where x is the number of images 1..67, y are 0, 1, 4, 8, 16, 32, 64, 128, 258. These files are randomly stored in the directory. I want to process the files in sorted order (same order which I have written above i.e Image