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Tag: generator

Can you yield from a lambda function?

I have a generator function in a class: In another function I initalize it as a variable: And it’s yielded as necessary: Can defining the generator be done in one line, however? I’ve considered the below: Here’s a minimal code I’m working with: Output is below: I just wanted to see if I could get rid of Foo.generator and instead

Iterables / generators with specified length

Iterable objects are those that implement __iter__ function, which returns an iterator object, i.e. and object providing the functions __iter__ and __next__ and behaving correctly. Usually the size of the iterable object is not known beforehand, and iterable object is not expected to know how long the iteration will last; however, there are some cases in which knowing the length

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