Is input arguments to a function returned always by default?

I have a function like given below. The code works fine and I require your assistance only in helping me to understand how the return or function output is stored. I am a beginner and your inputs would be helpful As you can see, I am only returning the result dataframe as output from the function. No other variables are returned from function When I call the function in sequence like below, I expect it throw an error at the last line for dataFramesDict[sheet_name] but it works fine. Shouldn’t I be getting an error message like below sheet_name isn’t defined

How do I write a function to run a function and return uniquely named outer-scope variables?

I need to run one function multiple times where 3 out of 5 arguments stay the same every time. How can I write a function to just take the unique arguments as inputs and return the outputs of the inner function as unique variables? The function I’m trying to run is part of SQLalchemy: The first argument, table name, is always different and should also be the name of the variable. The last argument will be different sometimes. My idea was to create a dictionary with table_name: schema_name and pass it to a function that loops through the dictionary and

Printing lines in a text file given line numbers

I am having trouble with a while loop statement for the question below. This is for a txt.file. ‘Write a program that allows the user to navigate through the lines of text in any text file. The program prompts the user for a filename and copies the lines of text from the file into a list. The program then prints the number of lines in the file and prompts the user for a line number. Actual line numbers range from 1 to the number of lines in the file. If the input is 0, the program quits. Otherwise, the program

How does one ignore unexpected keyword arguments passed to a function?

Suppose I have some function, f: Now, if I have a dictionary such as dct = {“a”:”Foo”}, I may call f(**dct) and get the result Foo printed. However, suppose I have a dictionary dct2 = {“a”:”Foo”, “b”:”Bar”}. If I call f(**dct2) I get a Fair enough. However, is there anyway to, in the definition of f or in the calling of it, tell Python to just ignore any keys that are not parameter names? Preferable a method that allows defaults to be specified. Answer As an extension to the answer posted by @Bas, I would suggest to add the kwargs

python max function using ‘key’ and lambda expression

I come from OOP background and trying to learn python. I am using the max function which uses a lambda expression to return the instance of type Player having maximum totalScore among the list players. The function correctly returns instance of type Player having maximum totalScore. I am confused about the following three things: How does the max function work? What are the arguments it is taking? I looked at the documentation but failed to understand. What is use of the keyword key in max function? I know it is also used in context of sort function Meaning of the