So I’m trying to get this working, where I remove the week’s stats (weeklydict) from this second’s stats (instantdict) so I have an accurate weekly progress for all keys of instantdict (keys being members). It works fine and dandy, but when a new member joins (adding to the keys in instantdict), shit hits the fan, so I use try/except, and
Tag: dictionary
Python datastructure for keys being mapped to auto-increment integer value
I want to store a list of strings into a dictonary data structure, where the key will be the string I provided, and the value will be an auto-increment count. I could do this by keeping a manual counter and then using that when inserting values in a dictionary, but I wanted to know if there is any default data
Python – Find distinct domains inside a list of dictionaries
I have a list (with dictionaries inside) and I want to know how many different domains are inside it. I have something like this: The desired result would look like this: Or maybe just: Both would be OK, so whatever is easier or faster I guess. I think I could use Regex for this, but maybe there are more pythonic
Sorting by word count that store in dict python
how can you sort by word count? sorted() sort me only by the number of numbers? Thank you for your help input is print(make_dict(“test is test tests tests tests”)) output is {‘test’: 2, ‘is’: 1, ‘tests’: 3} im search output tests ,test ,is Answer You can change your code like approach_1 or use collections.Counter like approach_2. You can sorted on
How do I change a key’s value to that of another key’s value if the value is the name of another key?
To explain what I mean, I’m adding keys and values to a dictionary but if a key in the dictionary has a value that’s the name of another key, I want that key to be assigned the other key’s value. For example, if I have dict1 = {“a”: 100, “b”: 200, “c”: “a”} is it possible to change the value
Get the key from a sub-dictionary and a value from a list of key-val pairs within it
I have a dictionary called metadata. It has a length of 2 keys, ‘status’ and ‘data’. I am only interested in the key ‘data’ and what lies within it. The subdictionary ‘data’ has 1,136 keys. Within ‘data’ I need the Key and the Value of the 1st position (i.e. second elelment). For example the first Key within ‘data’ would be
Finding any changes between two lists of the same length
Given 2 lists of the same length. Is it possible to return a dict containing any changes between the 2 lists. Each key being the value that was changed and the key’s value being the value it was changed to. The following returns difference between the 2 lists: I am looking to go one step further and save the results
How to create a dictionnary whose key:value pairs are the values of two different lists of dictionnaries?
I have 2 lists of dictionnaries that result from a pymongo extraction. A list of dicts containing id’s (string) and lemmas (strings): lemmas = [{‘id’: ‘id1’, ‘lemma’: ‘lemma1’}, {‘id’: ‘id2’, ‘lemma’: ‘lemma2’}, {‘id’: ‘id3’, ‘lemma’: ‘lemma3’}, …] A list of dicts containing id’s and multiple words per id: words = [{‘id’: ‘id1’, ‘word’: ‘word1.1’}, {‘id’: ‘id1’, ‘word’: ‘word1.2’}, {‘id’: ‘id2’,
How to fill nested dict when you only have a list of key, value for the final layers?
I have a nested dict of the folling form: And a flat dict with only the values in the final layer: My expected output after filling the values in the first dict would be: How should I approach this? Answer I hope I’ve understood your question correctly. You can use recursion to replace the values of keys in-place: Prints:
How to print dict key value dynamically?
I’m trying to print a dict key value dynamically. EX: As we see the key ‘waninfo’ and ‘1’ are fixed and i would like to use the keys after dynamically, like this: How can i do this? Answer If there’s a constant number of keys, it might be easiest to just declare separate variables for them: If you have a