Tag: regex

Python Regex – Reference first line on every match, until the start of a new group

Sample text: Intended result: Regex Attempts: (?:^This is (?P<H>HeaderB)s) (Line (?P<L>d)s)*? Matches only the Header ‘H’ and 1st ‘L’ Line (?:^This is (?P<H>HeaderB)s)? (Line (?P<L>d)s)*? manage to match multiple ‘L’ Lines however, only first 2 line are of the same match, not the subsequent L lines does not reference the Header capture group. I tried other attempts to adjust the

regex for finding gene product from the text

bioinformatics python regex

What regex should I use for matching such text by far I have tired this pattern: Answer Use See regex proof. EXPLANATION

Regex: Remove the letters with length 1-3 which are before the dot

python regex

If I have an input something like this Another example is I want to produce a code which is generalized for any group of letter in any language. This is my code So I can change ‘A’ with any other letter, but for some reason isn’t working well. I tried also this one but isn’t working as well. Answer Try

How to automatically remove space before punctuation

python regex

For example: “This is some text . This is some text” should be “This is some text. This is some text” We can use replase but replacing ‘ .’ with ‘.’, but it’s not a good approach. Please let me know if you have any other idea which is generalised for any punctuation. Answer Sorry I’m on mobile but it

Remove unwanted str in Pandas dataframe

pandas python regex

‘I am reading a csv file using panda read_csv which contains data, In the last column, I want to remove the Index, Step, data= and want to retain the hex value part. I have created a list with the unwanted values and used regex but nothing seem to work. Answer I suggest that you fix your code using The ‘|’.join([re.escape(x)

Translating python raw string / regex to ruby

python regex ruby string

I’m currently trying to translate a python script to ruby. Now I’m stuck on a part that uses a raw string for a regex. This is the original python code: This is my attempt to translate it to ruby: Unfortunately I must be doing it wrong because I get this error: I also tried: But it results in the same

How to parse and match with multiple regexes

parsing python regex

I have an input data of the form: I need to parse through this data and the IN: / OUT: /INOUT: depending on three regexes given as: My output should be: The code I tried: The problem I face is that it does not parse correctly and it is not getting matched for each subdata beginning with [2] Answer Though

Search in string and replace with a value from a list in python using regex

find python regex replace

I want to put this value of the list into my_string. So, my_string would be: “”” Hello John, I would like to work with you. I need your help to complete my project. Regards, Doe “”” Here, number of [placeholder] and length of the list would be dynamic. So, I need a dynamic solution. That will work for any string

Extracting Multiple Parameters from a String using Regex or Pandas

pandas python regex

I’m working with the following DataFrame Consisting of parameters (bphigh bplow weight) of type stras follows {u’bphigh’: u’120′, u’bplow’: u’70’, u’weight’: u’84.8′} I’d like to extract these parameters and their corresponding values to columns as shown below I tried using the following pandas method which hasn’t really been consistent in extracting the parameters vitals[‘vital’].str.extract(r”{u’bphigh’:s*(w+)”) Is there a more efficient workaround

Python regex to replace a Particular line in paragraphs as per regex only not whole file

python regex regexp-replace replace

Now python code to re.sub to replace UNWANTED TEXT only inside paragraphs keep UNWANTED TEXT Outside paragraphs But the output replace all instance of UNWANTED TEXT in through out the file but i expect like this Please help. Answer Your demo input should have been more ‘minimal’. However, I tried to understand your requirement and I tried re.split works: Output: