I have the following table with 4 columns: My desired Output in a df: I need it to loop through and combine all possible combinations. What is the best way to do this using python? Answer I assume that by table you mean a pandas dataframe, so the first step would be to collect the columns of interest into a
Tag: python-itertools
Too many combinations
Hi I’m trying to generate all possible combinations of workers to buildings. (let me explain my scenario): I’m playing MineColonies on minecraft. In this mod you have colonists whom can be assigned jobs at buildings. These workers have skills and a score assigned to them. (like Agility: 20, Strength:5 etc) and the work at the buildings are performed better when
Generating Maximal Subsets of a Set Under Some Constraints in Python
I have a set of attributes A= {a1, a2, …an} and a set of clusters C = {c1, c2, … ck} and I have a set of correspondences COR which is a subset of A x C and |COR|<< A x C. Here is a sample set of correspondences COR = {(a1, c1), (a1, c2), (a2, c1), (a3, c3), (a4,
itertools’ islice(count()) vs range()
Real quick one: I just saw a tutorial where they show we can use itertools’ islice() and count() together like so: Is there any advantage in doing this instead of using range() ? Answer Is there any advantage in doing this instead of using range() ? In this example there is no advantage and range would be the canonical solution.
Removing Brackets from itertools combination list results
I have this code The output is: I want to remove the brackets and speech marks from the output. How can I achieve that? so that my output would be: Answer You can accomplish this in the following way (without using str.join): This should have the added benefit of avoiding the creation of intermediate strings in the join.
Separate combination of two separate lists keeping the correspondence/dependence on each other
I have two lists of same length which have one to one correspondence: I want to find combinations of these two lists separately. But the indices of combined elements must be the same for both lists. For example, if I do: I may get I could’ve got too because both are the same. So whatever the combination I get I
Create iterator to return elements from each iterable one by one
I was learning the itertools module and I am trying to make an iterator to return each element from the iterables provided as input. with one more rider that if say the lists are not of the same length then next(it) should return elements from the longer list when the shorter one runs out. Attempt at solution Which kind of
itertools group by multiple keys
I am using itertools to group by a dictionary key using the below: However I would like to group by ‘device_id’ and ‘port_id’ if possible, how can I add an additional key to the grouping? Answer Just use a tuple as key:
How to repeat each of a Python list’s elements n times with itertools only?
I have a list with numbers: numbers = [1, 2, 3, 4]. I would like to have a list where they repeat n times like so (for n = 3): [1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4]. The problem is that I would like to only use itertools for this, since I am very constrained
One line repeating counter with itertools?
I want to write an infinte generator using itertools that combines a the count and repeat iterators, by repeating each number n times before incrementing. Is there a more concise way to do it than what I came up with? Answer Use integer division!