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Tag: methods

Way to call method depending on variable?

I already have a working, but in my oppinion not beautiful solution for a part of a long script. My script uses several similar methods, that differ too much to combine. However I came to a point where I want to call one of those methods depending on a given variable. The names of the methods are build up like

Terminology: A user-defined function object attribute?

According to Python 2.7.12 documentation, User-defined methods: User-defined method objects may be created when getting an attribute of a class (perhaps via an instance of that class), if that attribute is a user-defined function object, an unbound user-defined method object, or a class method object. When the attribute is a user-defined method object, a new method object is only created

Override a “private” method in Python

Consider a class with a “private” method such as: When I try to subclass Foo and override method __method, it can be seen that Foo.__method is still called, instead of MoreFoo.__method. What would be the way to override such a method? Answer The point of using the double-underscore name convention is to prevent subclasses from (accidentally) overriding the method. If

How to get instance given a method of the instance?

Now can you get a reference to myInstance if you now only have access to methodReference? Answer If you are using Python 3: Otherwise: and by a similar token, for the class: For this kind of code discovery you should install iPython and use tab, for instance, in your case myReference.+TAB would give: Hence, you don’t need to worry about

dynamically adding callable to class as instance “method”

I implemented a metaclass that tears down the class attributes for classes created with it and builds methods from the data from those arguments, then attaches those dynamically created methods directly to the class object (the class in question allows for easy definition of web form objects for use in a web testing framework). It has been working just fine,

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