I have a list of tuples which in turn have 2 elements and a list. I wish to delete the tuples that have empty lists. Expected output: I tried : It throws me a Memory Error Answer One way using list comprehension with unpacking: Output:
Tag: list
How to convert a list with dictionaries into new pandas columns?
I have a dataframe which has a list of dictionaries as a column: This column has the following format: How can I convert this column into 4 new columns? I mean: route_id (x2), stop_id(x2) as new columns. Thanks in advance! Answer You can use df.explode with df.apply:
More pythonic way of item_list[-1] != item_list[-2]?
I’m updating and then referring to the last item added to a list to determine an outcome, for example: I don’t need to refer to any other list element, just item_list[-1] & [-2]. Is there a more pythonic way of doing this? This code is for on_message using websockets, and the item_list is bein…
Why is my attempt to iterate through a list of lists and update dictionary values resulting in unchanged dictionary?
I want to iterate through a list of lists and if an instance in the list matches a key in a dictionary, add 1 to that dictionary key value. However, when I execute my code it returns the dictionary with no changes to the values. Thank you for your time & help. I searched for a similar question but did
Remove elements from python list if they contain special characters
I have a python list of lists, where each row index represents a list of values. In some instances, the row values contain special characters. In the case that any list element in the row contains special characters, I want to remove that entire row from the list. Note that I want to do this without convertin…
How to remove items from dictionary list, for each value that’s in a list
I am trying to return a list of dictionaries exept for the dictionaries with the same id’s as in game_list_id This is what i got so far: Answer You can do that in a single line without a function:
Is there any possibility to create a new column based on the keywords list
Is there any possibility to create a new column based on the keywords list? I have data like this: I would like to create a new column if the keyword exists in the Type column and if 2 keywords exist then the value should both keyword with a comma. I am having a problem because I have to check also
Filter 2d list by another 2d list
I have a list A: And list B: I would like to leave only these rows in list A, that all values of which are contained in at least one row from list B. So my expected output is: Because values ‘512’ and ‘102’ are in second row of list B. I know how to achieve that by iterating or
Grouping a list of tuple which has two lists based on the second list
I have a sequence is like this, seq = [[[“A”,”AA”,”AB”],[0,1,2,3]], [[“B”,”BB”,”BC”],[1,2,3]], [[“C”,”CA”,”CB”],[0,1,2,3]]] I wanted to convert this to something like below [[[‘A’, ‘AA…
Modifying the contents of a list Python
Here’s the coursera Google question prompt that I’m having issues with: The skip_elements function returns a list containing every other element from an input list, starting with the first element. Complete this function to do that, using the for loop to iterate through the input list Original Cod…