for row in data[‘column_name’]: if row.date() < datetime.today().date(): print(row,????) I was not able to get the index of a datatime of a specific column in a dataframe. I used this code and i want to return with the row the index of the row. Could anyone help me please? Answer You can try with something as follows
Tag: indexing
How find index where the item length less than x in python
for example i have a list which contain: For example, I want to get the index of the item that the length is less than 30. How to do that?Is it possible? Answer you can use enumerate function and list comprehention for this:
Function to move specific row to top or bottom of pandas dataframe
I have two functions which shift a row of a pandas dataframe to the top or bottom, respectively. After applying them more then once to a dataframe, they seem to work incorrectly. These are the 2 functions to move the row to top / bottom: Note: I don’t want to reset_index for the returned df. Example: This is my dataframe:
Find the index of a nested dict within a list base on the dict’s nested value
i have a list of dicts how can i find the index of jane given only her phone number (8179482938)? Answer To get an index, you can do (lst is your list from question): Prints:
remove empty dataframe from list and drop corresponding name in second list
I have two lists, where the first one is a list of strings called names and has been generated by using the name of the corresponding csv files. I have loaded the csv files into individual pandas dataframes and then done some preprocessing which leaves me with a list of lists, where each element is the data of each dataframe:
python – using an index in one series to find values in a separate dataframe with matching index
I have a for loop that is taking a subsample of my original dataset, doing a prediction from a previously fit model, and then i need to match the target value from the original dataframe to the prediction to calculate a different value. 20 lines from original subsample: code: so, my “target” needs to find the index of each top_200
Two DataFrames, find index of second one where values of two columns match up from first
I have two pandas DataFrames as pictured. DF1: DF2 (192 x 7): I want to find the index value of DF2 where df1[0] & df1[1] match df2[0] & df2[2]. For more detail, this would be represented above as starting at index 3188 of DF2. DF1 values will be dynamically changing as DF2 stays constant. Edit: Just noticed that there was
I am confused in a part of my python code
Q-Given a string of lowercase letters in the range ascii[a-z], determine the index of a character that can be removed to make the string a palindrome. There may be more than one solution, but any will do. If the word is already a palindrome or there is no solution, return -1. Otherwise, return the index of a character to remove.
How to get all values in an array whose added index size is greater than value?
I have a 5×5 ndarray and want to sum up all values whose added index size is greater than a given value. For example, I have the following array and want to sum all values whose row and column index is, combined, larger than 6. If I do this manually, I would calculate because 4 + 3, 4 + 4
How to remove text in a list at each index
I have a list similar to: I need to modify the list to remove the first numbers only and display the list so that after each comma there is a new line. The expected output would be: I tried many codes but I’m lost now and don’t know how to arrive to my desired output. Answer One way would be