Html:
<div class="xxxx"> <a href="ooooo.pdf"></a> </div>
Python selenium code trials:
from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC print(wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div.xxxx a"))).get_attribute('href'))
Output:
aaaaa.pdf
How print ooooo.pdf
and aaaaa.pdf
?
I want to print more links, what should I do?
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Answer
element_to_be_clickable() returns a single WebElement hence href
attribute of only the first matching element is printed.
Solution
To extract all the href
attribute values you have to induce WebDriverWait for visibility_of_all_elements_located() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
print([my_elem.get_attribute("href") for my_elem in WebDriverWait(driver, 10).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "div.xxxx a")))])
Using XPATH:
print([my_elem.get_attribute("href") for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//div[@class='xxxx']//a")))])
Alternative
As an alternative you can also try:
Using CSS_SELECTOR:
print([my_elem.get_attribute("href") for my_elem in driver.find_elements(By.CSS_SELECTOR, "div.xxxx a")])
Using XPATH:
print([my_elem.get_attribute("href") for my_elem in driver.find_elements(By.XPATH, "//div[@class='xxxx']//a")])