I have a list of ‘widget types’, [“C”,”A”,”B”] and need to make a dict for those types to correspond to their respective ID’s, 1=’C’, 2=’A’, 3 = ‘B’, 4= ‘C’, 5=’A’, 6= ‘B’, 7 = ‘C’, etc. I already know how to do it, I just wondered if there was a more elegant pythonic way of achieving it than that
Tag: zip
How to create a file object from a zipfile?
I want to create a file object from a file that is inside a zip. I don’t wanna extract that file. Actually I wanna use seek method on a file that is inside a zip. My code: But I can’t use seek method on it. I wanna make it like this but without extracting the file: Answer The documentation says
Nested if statement returns no such item
my scipt is working as in searching for zip files, unzip and do the things i want. But problem arise when i have nested zip files inside the zip file, so i thought maybe i copy the working if statement, make a few adjustments but i still cant get it to work. what i want to achieve is to simply
Implemeting Zip(*iterables) using a For loop
I am trying to implement the zip(*iterables) function using a for loop and I am unable to do it. As you know, the zip function gets the first element of every list that’s passed into it, puts it in a tuple, then does the same with the second list of the elements in the list… and so on. In my
Python Bruteforcing zip file cannot assign to function call
I am learning how to access a zip file with python BruteForcing. but I am facing a problem when I do that in the zipF in line 11 that is the exception: cannot assign to function call. Thanks in advance Answer You can’t use a break inside a try-catch statement. also, you try to assign a function to the file
How to json dump inside Zipfile.open process?
I am trying to write a json inside a ZipFile BytesIO process. It goes like this: It is later saved in a Django File field. However it does not dump the data into the json_file. Finds it hard since it does not report an error message. Answer Your code ‘shadows’ zipfile, which won’t be a problem by itself, but would
How can I extract multiple .zip files?
I’m trying to extract multiple files from some .zip archives. My code is: However, it only extracts the files inside the first archive. I’m using Python 3.6. What is wrong? Answer I thought this scenario might be a serious candidate … What happens is that for each .zip file, all its members are extracted, but they overwrite the ones extracted
How to create zip64 archive using shutil.make_archive
Python code snippet which creates creates zip archive file from a folder. I am getting this error : Filesize would require ZIP64 extensions. How to create ZIP64 archive file using shutil.make_archive? Note: I cannot use zipfile.ZipFile function. Answer You must be using a Python version prior to 3.4 unfortunately after reading shutil source code on github github . it’s clearly
How do I zip an entire folder (with subfolders) and serve it through Flask without saving anything to disk
I have a folder structure on my web server that I would like to serve as a zipped archive through Flask. Serving a file through Flask is pretty straight forward through Flasks send_file: Zipping can get accomplished in various ways like with shutil.make_archive or zipfile, but i cannot figure out how to zip the whole directory in memory and then
Python/Pandas create zip file from csv
Is anyone can provide example how to create zip file from csv file using Python/Pandas package? Thank you Answer Use From the docs: compression : string, optional a string representing the compression to use in the output file, allowed values are ‘gzip’, ‘bz2’, ‘xz’, only used when the first argument is a filename See discussion of support of zip files