This is the regex code: It returns me the output of each URL which doesn’t have the https header in front. For example: For this, I want to append “https://example.com” in the beginning. I don’t want a for loop, is there any efficient way of doing it using re.sub? Answer You may use this regex in re.sub: RegEx Demo Code:
Tag: url
Python found URL is invalid
Hi there I have following Problem: I extracted a list of URL’s from a .txt file with Python using this: And the Output contains for some files following: PROBLEM IS: as you see it printed out “#038;” I’m thinking that translates into “&” but there is already a “&” infront of that and if I follow the Link its invalid.
Importing data from URL using Python (into pandas dataframe)?
I’ve gone around in circles on this one. A bit frustrating as the solution is probably close at hand. Anyway, I found a URL that returns some data in CSV format. However, the URL itself does not contain the csv file name. In a web browser, I can easily go to the link and them I’m asked whether I want
how to reverse the URL of a ViewSet’s custom action in django restframework
I have defined a custom action for a ViewSet And the viewset is registered to url in the conventional way The URL /api/users/gender/ works. But I don’t know how to get it using reverse in unit test. (I can surely hard code this URL, but it’ll be nice to get it from code) According to the django documentation, the following
Getting ‘wrong’ page source when calling url from python
Trying to retrieve the page source from a website, I get a completely different (and shorter) text than when viewing the same page source through a web browser. https://stackoverflow.com/questions/24563601/python-getting-a-wrong-source-code-of-the-web-page-asp-net This fellow has a related issue, but obtained the home page source instead of the requested one – I am getting something completely alien. The code is: This is the page
Django REST Framework and FileField absolute url
I’ve defined a simple Django app that includes the following model: (Technically yes, that could have been an ImageField.) In a template, it’s easy enough to include the MEDIA_URL value (duly coded in settings.py) as a prefix to the thumbnail URL. The following works fine: Using DRF, I’ve defined a HyperlinkedModelSerializer descendant called ProjectSerializer: And I’ve defined a very straightforward
URL query parameters to dict python
Is there a way to parse a URL (with some python library) and return a python dictionary with the keys and values of a query parameters part of the URL? For example: expected return: Answer Use the urllib.parse library: The urllib.parse.parse_qs() and urllib.parse.parse_qsl() methods parse out query strings, taking into account that keys can occur more than once and that
How do I add these headers to my python urllib opener?
opener.addHeaders(headers)? Answer Something like this may work: