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Tag: unique

frequency of unique values for 2d numpy array

I have a 2-dimensional numpy array of following format: now how to print the frequency of unique elements in this 2d numpy array, so that it returns count([1. 0.]) = 1 and count([0. 1.]) = 1? I know how to do this using loops, but is there any better pythonic way to do this. Answer You can use numpy.unique(), for

Python: Check for unique characters on a String

I’m asking the user to input a keyword and then remove any duplicate characters. Example: Input: balloon Output: balon I’ve tried this solution: List of all unique characters in a string? but it marks it as a syntax error. Any ideas? Answer For your answer, order is important. Here is a one line solution:

How do I remove duplicates from a list, while preserving order?

How do I remove duplicates from a list, while preserving order? Using a set to remove duplicates destroys the original order. Is there a built-in or a Pythonic idiom? Answer Here you have some alternatives: http://www.peterbe.com/plog/uniqifiers-benchmark Fastest one: Why assign seen.add to seen_add instead of just calling seen.add? Python is a dynamic language, and resolving seen.add each iteration is more

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