How to obtain this outputs from those inputs? Note that for examples 4, 5, 6 and 7 the regex should not make any changes, since after the word there is already a space placed, or because in the case of “uno”, the word “un” is not at the end of the sentence, or in the case of “treinta yun” the
Tag: regexp-replace
Reformatting a string to simulate a json using python regex
What I want to do is essentially reformat a string and make it pass the jsonschema validate function. Simple enough at face value. However, the tricky part is that the string is being read in from a file and can vary in it’s appearance and formatting. Example being OR Or any possible combination of single quotes, double quotes, no quotes,
Remove trailing .0 from strings of entire DataFrame
Hi I would like to remove all “.0” at the end of a string for an entire DataFrame and I need it to be an exact match. Let’s make an example df: The desired output: I tried using replace but it didn’t work for some reason (I read maybe because replace only replaces entire strings and not substrings?). Either way,
Python regex to replace a Particular line in paragraphs as per regex only not whole file
Now python code to re.sub to replace UNWANTED TEXT only inside paragraphs keep UNWANTED TEXT Outside paragraphs But the output replace all instance of UNWANTED TEXT in through out the file but i expect like this Please help. Answer Your demo input should have been more ‘minimal’. However, I tried to understand your requirement and I tried re.split works: Output:
How to Ignore html comment tag in regex through python
I am replacing special character with some asci code and ignoring html tags with the help of below regex text_list = re.findall(r’>([Ss]*?)<‘, html) So it is ignoring all html tags as we want it but is not ignoring html comment closing tag “–>”. Any help appreciated. What should I changed in regex. Attached screenshot for your reference. Answer Please try
How to append something to the beginning of Regex matches?
This is the regex code: It returns me the output of each URL which doesn’t have the https header in front. For example: For this, I want to append “https://example.com” in the beginning. I don’t want a for loop, is there any efficient way of doing it using re.sub? Answer You may use this regex in re.sub: RegEx Demo Code: