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Tag: python-3.x

Get the sum of each column, with recursive values in each cell

Given a parameter p, be any float or integer. For example, let p=4 time 1 2 3 4 5 Numbers a1 a1*(0.5)^(1/p)^(2-1) a1*(0.5)^(1/p)^(2-1) a1*(0.5)^(1/p)^(3-1) a1*(0.5)^(1/p)^(4-1) Numbers nan a2 a2*(0.5)^(1/p)^(3-2) a2*(0.5)^(1/p)^(4-2) a2*(0.5)^(1/p)^(5-2) Numbers nan nan a3 a3*(0.5)^(1/p)^(4-3) a3*(0.5)^(1/p)^(5-3) Numbers nan nan nan a4 a4*(0.5)^(1/p)^(5-4) Number nan nan nan nan a5 Final Results a1 sum of column 2 sum of column 3

Need Help extracing a list from a string using regex

I have a little trouble extracting these two lists ‘[‘item1’, ‘item2’, ‘item3’] [‘item4’, ‘item5′]’ here is an example of the code I have attempted The output I received was I would like to know how I can go about extracting these two lists from this long string specifically [‘item1’, ‘item2’, ‘item3’] and [‘item4’, ‘item5’] Answer Result: Explanation: [ matches the

Best way to find the last number in a String

I have images with variable names, the only consistant feature/thing is that the image number is located at the end of the name, just before the extension. For example: “im1.png”, “Image 02.tif”, “My3rdImage_3.jpg” , “Whatever_17_MoreWhatever-31.tiff”. What would be the best way to find the last number? I can always do: Find the last point. Go back while I detect digits

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