Tag: if-statement

Python: more elegant way to assert type of function input

I am a complete beginner in Python… Currently I am trying to write a function which first checks whether the inputs x and y are int or float. My guess which does the job is if (type(x) != int and type(x) != float) or (type(y) != int and type(y) != float): However, this seems quite clumsy / inefficient to me

Should I be using an if statement or a loop?

if-statement python while-loop

It’s me, your friendly Python noob! I’m working on this program and I’m trying to figure out how to get the program to stop if the number exceeds a certain threshold OR if the user enters anything other than a number to loop back around and try again. Here is what I have so far: The if statements in main()

How to replicate same values based on the index value of other column in python

dataframe if-statement pandas python string

I have a dataframe like below and I want to add another column that is replicated untill certain condition is met. Now I want to add another column which contains additional information about the dataframe. For instance, I want to replicate Yes untill id is B and No when it is below B and Yes from C to D and

The else function does not appear even if the “if” conditions are not met [closed]

if-statement loops python python-3.x

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers. Closed 2 years ago. Improve this question

if else Conditions

conditional-statements if-statement python

The problem is like this My solution: Now, if I enter 18 then it should be printed “Weird”. But it is showing “Not Weird”. I am not getting where the problem of my code is. Answer The operator & is the bitwise and operation. You need logical AND, instead, and it is done by means of and keyword. Just replace

Coverage for one-liner if statement

coverage.py if-statement pytest python

Static code analyzers for Python do not generate branches in the following case (one-liner if). Is this by design? Even coverage gives 100% coverage even if only one case is tested. Can anyone please shed some light on this? Answer The first comment says “does not create a control structure.” I don’t know what that means. Whether it’s one line

Automate the Boring Stuff – Chapter 5 – Chess Dictionary Validator [closed]

dictionary for-loop if-statement python

Closed. This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 9 months ago. Improve this question First post, new to programming and having fun! All feedback on this post and my questions are welcome. I’m working

Why does it ignore my continue in the for-loop? [closed]

continue for-loop if-statement pygame python

How to avoid using global variables?

function global-variables if-statement python python-3.x

I use global variables but I’ve read that they aren’t a good practice or pythonic. I often use functions that give as a result many yes/no variables that I need to use in the main function. For example, how can I write the following code without using global variables? Answer One could ask what reasons you might have to structure