I have a function that checks Fibonacci numbers for even. I need it to output a specified number of even numbers Example input: 4 Example output: 0 2 8 34 Answer You could just go over the even ones directly: Consider two adjacent Fibonacci numbers a and b (initially 1 and 0) and what happens when you shift the window:
Tag: fibonacci
How to find nth Fibonacci number using Javascript with O(n) complexity
Trying really hard to figure out how to solve this problem. The problem being finding nth number of Fibonacci with O(n) complexity using javascript. I found a lot of great articles how to solve this using C++ or Python, but every time I try to implement the same logic I end up in a Maximum call stack size exceeded. Example
How to write a generator class?
I see lot of examples of generator functions, but I want to know how to write generators for classes. Lets say, I wanted to write Fibonacci series as a class. Output: Why is the value self.a not getting printed? Also, how do I write unittest for generators? Answer How to write a generator class? You’re almost there, writing an Iterator
What am doing wrong in this piece of fibonacci code in python docs vs my re implementation?
Python docs: My reimplementation: Answer The difference between and is that in the second one, a is assigned value of b, and then b is assigned the sum of a and b, which means it is twice its original value. Consider: This gives Contrarily: which gives:
Efficient calculation of Fibonacci series
I’m working on a Project Euler problem: the one about the sum of the even Fibonacci numbers. My code: The problem’s solution can be easily found by printing sum(list2). However, it is taking a lot of time to come up with the list2 I’m guessing. Is there any way to make this faster? Or is it okay even this way…
Finding the sum of even valued terms in Fibonacci sequence
My algo: If I take first 2 numbers as 0, 1; the number that I find first in while loop will be an odd number and first of Fibonacci series. This way I calculate the even number and each time add the value of even to total. If value of even is greater than 4e6, I break from the infinite