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Tag: duplicates

Pandas – Duplicate Rows and Slice String

I’m trying to create duplicate rows during a dataframe on conditions. For example, I have this Dataframe. And I would like to get the following output: Answer For pandas 0.25+ is possible use DataFrame.explode with splitted values by Series.str.split and for remark column list comprehension with filtering: And we get the following result:

Remove duplicates and combine multiple lists into one?

How do I remove duplicates and combine multiple lists into one like so: function([[“hello”,”me.txt”],[“good”,”me.txt”],[“good”,”money.txt”], [“rep”, “money.txt”]]) should return exactly: Answer Create a empty array push the index 0 from childs arrays and join to convert all values to a string separate by space .

Count duplicate lists inside a list

I want the result to be 2 since number of duplicate lists are 2 in total. How do I do that? I have done something like this But the count value is 1 as it returns matched lists. How do I get the total number of duplicate lists? Answer Solution You can use collections.Counter if your sub-lists only contain numbers

Checking if a list has duplicate lists

Given a list of lists, I want to make sure that there are no two lists that have the same values and order. For instance with my_list = [[1, 2, 4, 6, 10], [12, 33, 81, 95, 110], [1, 2, 4, 6, 10]] it is supposed to return me the existence of duplicate lists, i.e. [1, 2, 4, 6, 10].

Remove duplicates from a dataframe in PySpark

I’m messing around with dataframes in pyspark 1.4 locally and am having issues getting the dropDuplicates method to work. It keeps returning the error: “AttributeError: ‘list’ object has no attribute ‘dropDuplicates'” Not quite sure why as I seem to be following the syntax in the latest documentation. Answer It is not an import problem. You simply call .dropDuplicates() on a

How do I remove duplicates from a list, while preserving order?

How do I remove duplicates from a list, while preserving order? Using a set to remove duplicates destroys the original order. Is there a built-in or a Pythonic idiom? Answer Here you have some alternatives: http://www.peterbe.com/plog/uniqifiers-benchmark Fastest one: Why assign seen.add to seen_add instead of just calling seen.add? Python is a dynamic language, and resolving seen.add each iteration is more

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