Novice in python! A numpy array A of 1000 elements consists of fixed values between -100 to +100. These 201 values are nothing but categories. Another numpy array B has the approximations of the values for each category of A. Both A and B are of same length. For example A=[-100, -100, -88, 87, 85, 32, 32, 32] and corresponding
Tag: dictionary-comprehension
How do I convert dict of dicts/nested dicts into dict of list
Heres the original dict What I am trying to get The keys in original dict represent uid. This is my what I have done: But I am rather looking for a generalized approach, to achieve without manually declaring the keys again, just so it should work with new keys in the original data. Answer Generalized (based on original version by
How to look for specific values in a dictionary and return them properly
So I have a list dictionary of dictionaries (lst) that I’m trying to iterate through, compare values, and return the appropriate values. I have the following code to retrieve 2 arguments given from the command line, compare them through the dictionaries entries, and return the appropriate value: get_attribute_number(cmd1=sys.argv[1], cmd2=sys.argv[2], lst=data_list) However, my program is not returning anything. It is supposed
Convert a list of objects to a dictionary of lists
I have a list of JSON objects, already sorted (by time let’s say). Each JSON object has type and status. For example: I’d like to convert it to: So of course it’s an easy task but I’m looking for the Pythonic way doing that, so it will spare me a few lines of code Answer I don’t know if there
replace client’s id with their respective name in shipment dictionary using a loop and dictionary comprehension
d1={101:{‘Sender’:1,’Receiver’:3,’Start date’:’14-03-2020′,’Delivery date’:’25-03-2020′,’Sender location’:’Area 1′,’Receiver location’:’Area 6′,’Delivery status’:’Delivered’,’Shipping cost’:198}, 102:{‘Sender’:4,’Receiver’:1,’Start date’:’18-06-2020′,’Delivery date’:’09-07-2020′,’Sender location’:’Area 2′,’Receiver location’:’Area 4′,’Delivery status’:’Delivered’,’Shipping cost’:275}, 103:{‘Sender’:2,’Receiver’:3,’Start date’:’01-12-2020′,’Delivery date’:’Null’,’Sender location’:’Area 5′,’Receiver location’:’Area 1′,’Delivery status’:’In Transit’,’Shipping cost’:200}, 104:{‘Sender’:1,’Receiver’:5,’Start date’:’23-06-2020′,’Delivery date’:’25-06-2020′,’Sender location’:’Area 1′,’Receiver location’:’Area 4′,’Delivery status’:’Delivered’,’Shipping cost’:314}, 105:{‘Sender’:3,’Receiver’:4,’Start date’:’29-08-2020′,’Delivery date’:’10-09-2020′,’Sender location’:’Area 5′,’Receiver location’:’Area 3′,’Delivery status’:’Delivered’,’Shipping cost’:275}, 106:{‘Sender’:5,’Receiver’:2,’Start date’:’28-06-2020′,’Delivery date’:’Null’,’Sender location’:’Area 3′,’Receiver location’:’Area 1′,’Delivery status’:’In Transit’,’Shipping cost’:270}} d2 = {1:’Phillip’,2:’Omega lll’,3
Creating list of dictionaries from a dictionary using list comprehension
I have a dictionary of the format: And I’m trying to create a list of dictionaries that separate the values, i.e., the result should be: Is there a way I can do this with a one-line list comprehension? What I have tried so far: And my code using a normal “for” loop: Answer Here’s a list comprehension + dictionary comprehension
How to generate dictionaries from multiple lists?
I have the following lists : And I would like to generate the following dictionaries: Which kind of loop or function Should I use? Answer Use zip and the following comprehension:
Expand a dict containing list items into a list of dict pairs
If I have a dictionary containing lists in one or more of its values: How can I get a list of dict tuples paired by pair and iterating over c, with all else remaining constant? E.g. Answer Well, this doesn’t feel especially elegant, but you might use a nested for loop or list comprehension: or A cleaner solution might separate
Return copy of dictionary excluding specified keys
I want to make a function that returns a copy of a dictionary excluding keys specified in a list. Considering this dictionary: A call to without_keys(my_dict, [‘keyB’, ‘keyC’]) should return: I would like to do this in a one-line with a neat dictionary comprehension but I’m having trouble. My attempt is this: which is invalid syntax. How can I do