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Tag: dataframe

Get the sum of each column, with recursive values in each cell

Given a parameter p, be any float or integer. For example, let p=4 time 1 2 3 4 5 Numbers a1 a1*(0.5)^(1/p)^(2-1) a1*(0.5)^(1/p)^(2-1) a1*(0.5)^(1/p)^(3-1) a1*(0.5)^(1/p)^(4-1) Numbers nan a2 a2*(0.5)^(1/p)^(3-2) a2*(0.5)^(1/p)^(4-2) a2*(0.5)^(1/p)^(5-2) Numbers nan nan a3 a3*(0.5)^(1/p)^(4-3) a3*(0.5)^(1/p)^(5-3) Numbers nan nan nan a4 a4*(0.5)^(1/p)^(5-4) Number nan nan nan nan a5 Final Results a1 sum of column 2 sum of column 3

How to get a value in a column as an index

I assign the eligible index value to A column and then df.ffill() Now I want to use the value of A column as an index and assign the obtained value to the expcted column I try df[‘expected’]=df[‘price’][df[‘A’]] but it doesn’t work. input expected result table Answer Try this:

Separate columns of a DataFrame by days of the week

Let it be the following Python Panda Dataframe (the original could include dates for several months): Hours 2022-06-06 2022-06-07 2022-06-08 2022-06-09 2022-06-10 2022-06-11 2022-06-12 2022-06-13 2022-06-14 2022-06-15 2022-06-16 2022-06-17 2022-06-18 2022-06-19 00:00 3 0 0 3 23 43 1 2 3 3 7 3 1 0 05:00 5 4 0 3 32 31 3 9 3 3 5 3 0

How add value in second row into first row?

I would like to add a new columns from a values of ‘Pr’ in second rows for each value same id and date. Input a: ID Date order Date restock Pr Infos 778005 2022-04-07 11:34:46.0 NaN 87.0;113001.0;00 a 778005 2022-04-07 11:34:46.0 NaN 87.0;113159.0;FC at 7001 2021-12-10 13:50:46.0 2021-12-13 00:00:00.0 87.0;271007.0;BV b 7001 2021-12-10 13:50:46.0 2021-12-13 00:00:00.0 87.0;286005.0;BV bt 778005 2022-05-24

How do I append a repeating list to a dataframe?

I have a list sub = [“A”,”B”,”C”,”D”,”E”,”F”] and a dataframe of the following format: I need to write a code for my dataframe to finally look like the following format: Answer You can create a cycle using itertools.cycle, and cut it to the appropriate length using itertools.islice. So, in your case, you can just cut it to the length of

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