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Tag: binary-search

Binary search through string tuple in list

I’m trying to do a binary search through a list of tuples, when I give a inputq = “BB”, it is not show a correct search. This is my data: This my code: when I give inputq = “BB” the output it always show like this: (‘BF’, ‘Burkina Faso’, 13.0, -2.0) I would like to show my output like this

Find the indices where a sorted list of integer changes

Assuming a sorted list of integers as below: I want to find the indices where the values changes, i.e. One approach is to use itertools.groupby: Output This approach is O(n). Another possible approach is to use bisect.bisect_left: Output This approach is O(k*log n) where k is the number of distinct elements. A variant of this approach is to use an

Why does a function in a class does not return anything?

For exercising reasons, I am trying to implement a class SSM which stands for Static Sorted Map in python in order to implement the methods min_value(self) : find the minimum value max_value(self) : find the maximum value search(self, key): to find an element in the list The list is assumed to be sorted. Here is the code for the class:

What are python’s equivalents of std::lower_bound and std::upper_bound C++ algorithms?

Does python provide functions for performing binary search on sorted lists, analogous to the std::lower_bound and std::upper_bound algorithms of the C++ Standard Library? Answer Those functions are located in the bisect module: bisect.bisect_left(a, x, lo=0, hi=len(a)) is the analog of std::lower_bound(). bisect.bisect_right(a, x, lo=0, hi=len(a)) is the analog of std::upper_bound(). Note: there is also a function bisect() which is an

Binary search (bisection) in Python

Is there a library function that performs binary search on a list/tuple and return the position of the item if found and ‘False’ (-1, None, etc.) if not? I found the functions bisect_left/right in the bisect module, but they still return a position even if the item is not in the list. That’s perfectly fine for their intended usage, but

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