In python, I can do something like
a = [1,100,5,-5,-7,99,-100] a.sort(key= lambda x: (x<0,abs(x)))
It gives me
[1, 5, 99, 100, -5, -7, -100]
It is sorted by positive/negative number and abs value.
How can I do the same thing in R? Without splitting into positive and negative numbers?
a = c(1,100,5,-5,-7,99,-100)
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Answer
Use the order()
function:
a = c(1,100,5,-5,-7,99,-100) a[order(a < 0, abs(a))] #> [1] 1 5 99 100 -5 -7 -100
Created on 2022-03-22 by the reprex package (v2.0.1)
Another possibility which is useful in some situations is to define an xtfrm
method for a class. For example, if you know the values are all less than 1000, you could use
class(a) <- "classa" xtfrm.classa <- function(x) { (a < 0) + abs(a)/1000 } sort(a) #> [1] 1 5 99 100 -5 -7 -100
Created on 2022-03-22 by the reprex package (v2.0.1)