My goal is to create two groups from a full phone number(which is given in a string): First group: +xyz (any three numbers with a plus sign) Second group: following 7 or 8 digits So, my regex is: ((D?[0-9]{3})(D?s?[0-9]{7,8})) The problem I encountered was that if I have, for example +358 55667788, whitespace after a country code is still included
Tag: regex
Replace with Python regex in pandas column
There are many values starting with ‘^f’ and ending with ‘^’ in a pandas column. And I need to replace them like below : Answer You don’t mention what you’ve tried already, nor what the rest of your DataFrame looks like but here is a minimal example: Output
Match everything except a complex regex pattern and replace it in Pandas
I have a complex regex pattern to match mixed dates for a csv column in pandas df. I would like to replace everything except the regex pattern match with “” . I have tried pretty much all the negation cases (^ ?! and others). But I keep replacing the regex match with “” (empty string). My Code: Some examples of
Using regular expression for a field name in a Django
I have a model in Django that has the fields photo_1, photo_2, photo_3 and many other fields that does not contains the “photo” string on their names. Also, the photo fields can be blank, so I can find some rows with empty photo fields. For the html template, is there a way to go through the fields named “^photo_[0-9]*$” and
Reject optional whitespaces after area code and before local number (US)
I have a regex that parses US phone numbers into 3 strings. it works perfectly on the numbers: Now I need to add an additional regex to generate a Value Error for numbers such as I tried but non rejects the string in question I will greatly appreciate any ideas. I am very new to Regex! Answer In Python re
escaping square brackets from string in dataframe
I have a dataframe where i am try to clean the data from all cols. There are some annomalies in teh data like this: “[n], [ta], [cb]” basically anything in square brackets i want to ignore and replace with a space. I have this: this works except I still get the square brackets in the data but they are just
Python Regex pL matching issues
I’m trying to match a list of keywords I have, taking care to include all Latin characters (e.g accented). Here’s an example gives: Which looks correct. However: gives: This is wrong, as I expect a match for “u blah”. I’ve tried to also use Pythons built in re module, but I cannot get it to work with pL or p{Latin}
Find bit sequences that do not include specific sequence
I’m trying to find all non-overlap bit sequences satisfied the following constraints: starts with 0 ends with 110 or 111 does not contain 000 Here is my non-regex code in python: My current regex pattern is (0(^(?!000))*(?:110|111)). It doesn’t accept any bit between starting 0 and ending bits. For example, 010110 will return 0110 instead of expected 010110. Adding d*?,
How to find specific text with it’s correspondence value from a text input using Regex and Python?
I have some text input and I want to extract few information from the text. For that, I am trying to use Regular Expression and am able to do that except for two fields- rent and transfer. The input text is as below- Now I want to extract rent like- rent 500.00 and transfer as transfer 200.00 but somehow only
Regex to keep one choice in square bracket
I am trying to write a regex to replace the whole square bracket with the first choice. For example, [ choice A | choice B ] I want to replace the previous square bracket as a whole with choice A. However, when I have more than one of these brackets: [ choice A | choice B ] and choose between