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Tag: operators

Using multipe operators in Python sequentially

I’m trying to understand how Python handles using multiple sequential operators to add and subtract numbers. Here is an example of what I mean: I don’t understand what decides whether to add or subtract these two integers. I’ve used Python 3.11.1 for this example. Answer To understand how those expressions are evaluated you can use the ast (abstract syntax tree)

How is floor division not giving result according to the documented rule?

Why floor division is not working according to the rule in this case? p.s. Here Python is treating 0.2 as 0.20000000001 in the floor division case So (12/0.2000000001) is resulting in 59.999999… And floor(59.999999999) outputting 59 But don’t know why python is treating 0.2 as 0.2000000001in the floor division case but not in the division case? Answer The reason why

Invalid syntax using += operator [duplicate]

This question already has answers here: UnboundLocalError trying to use a variable (supposed to be global) that is (re)assigned (even after first use) (14 answers) Closed 5 months ago. I keep getting a syntax error when using += in python here is my code. I am also having troule with nonlocal. I am getting lots of errors including syntax errors

New operators in Python

We can define intrinsic operators of Python as stated here. Just for curiosity, can we define new operators like $ or ***? (If so, then we can define ternary condition operators or rotate operators.) Answer Expanding on @fasouto answer, but adding a bit more code. While you cannot define new operators AND you cannot redefine existing operators for built-in types,

Does Python have a ternary conditional operator?

Want to improve this post? Provide detailed answers to this question, including citations and an explanation of why your answer is correct. Answers without enough detail may be edited or deleted. Is there a ternary conditional operator in Python? Answer Yes, it was added in version 2.5. The expression syntax is: First condition is evaluated, then exactly one of either

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