This is my sample database: In my script now, I am adding elements to the list with the following code: So now if type “2 JO” my list will have two new elements “John” and “John”. Now I want to do exactly the same but for eliminating objects of a list. I tried to replace the current operator “+=” for
Tag: list
Filter column value from other columns’ values and turn the results into multiple lists Pandas
The goal is: for column 1990-1993, if value == 1, return Country to 4 lists, I also want to set each list a #name of the year and don’t know how to do that. here is my try: I got the output as 4 lists of nans… The desired output would be Answer One way using dict comprehension with groupby
Removing punctuation from only the beginning and end of each element in a list in python
I’m fairly new to python (and this community), this is a question branching off of a question asked and answered from a long time ago from here With a list like: Creating a new list x with no punctuation (and deleting empty elements) would be: Output: However, how would I be able to remove all punctuation only from the beginning
Сonvert list values to dictionary as key and value
Suppose there is a list: [‘1604780184′, ’10’, ‘1604780194’, ‘0’, ‘1604780319’, ’99’, ‘1604780320’, ‘0’] You need to get a result like: {‘1604780184′: ’10’, ‘1604780194’: ‘0’, ‘1604780319’: ’99’, ‘1604780320’: ‘0’} Now I have so: Please advise a better way. Thanks. Answer Most concise (and probably the best) way might be: What it actually does is make use of some pattern your list
How to remove multiple substrings at the end of a list of strings in Python?
I have a list of strings: If at the end of the string there is the word limited, com or org I would like to remove it. How can I go about doing this? I have tried; I’ve also tried the replace function with no avail. Thanks Answer You can use this example to remove selected last words from the
Compute cummulative sum until a zero appears
I have a (long) list in which zeros and ones appear at random: list1 = [1, 1, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1] 1.I want to get another list the sum of the list up to where 0 appears where 0 appears, retain 0 in the list list2 = [3, 0, 2, 0, 1, 0, 3]
Occurence of a value in many lists
i have a Series Object in pandas with 2 columns, one for the indices and one with lists, I need to find if a value occurs in only one of these lists and return it with the most optimal way. As an example let’s say we have this i need to return 77 because it occurs in only one of
Saving a new list from a a larger list using a loop
I have a large list, which I am pulling out every nth value from the first value up to the mth value to create new lists and I am using a for loop. My question is, how do I create a new list variable each time through the for loop? By way of simple example, I have the list: Which
Browse a dynamic json that contains nested lists and dictionaries
I have multi-levels json files with nested list and dictionnary inside, they look like this, but vary in size, and levels: I’m trying to read the json and print every single key value combination. When I’m at the end of a nested list, I would like to execute a function, let’s say for the moment one that do print(“This is
Deleting the last character in print statement when using for loop
I have created a list of numbers that are being inserted in a string, in this case it is a json. I am trying to delete the last character of the string after the list goes through and prints the very last element. I need to remove the last character which is a comma “,” in my string, only after