Sort a list according to the ascending sort of the second list in python

I have two unsorted lists, x and y, as follows:

x = ["a", "b", "c", "d", "e"] 
y = [ 5,   1,   4,   2,   3] 

I would like to sort list y two times, one in ascending order and then in descending order. But, in each sorting of y, I need to sort also the corresponding elements of the list x accordingly. Both lists have the same length of items.

I tried with the following code, but it is not working as expected:

def sort_list(list1, list2): 

    zipped_pairs = zip(list2, list1) 

    z = [x for _, x in sorted(zipped_pairs)] 
  
    return z 

print(sort_list(x, y)) 

Expected output: in case of ascending order

x = [ "b", "d","e", "c", "a"] 
y = [  1,   2, 3, 4,  5] 

Any help?

Answer

Just zip y and x – in this order, so that you can sort the resulting tuples in natural order, by their first item.

You can then sort, and zip again:

x = ["a", "b", "c", "d", "e"] 
y = [ 5,   1,   4,   2,   3] 

sorted_y, sorted_x = zip(*sorted(zip(y, x)))

print(sorted_x, sorted_y)
#('b', 'd', 'e', 'c', 'a') (1, 2, 3, 4, 5)

In reverse order:

sorted_y, sorted_x = zip(*sorted(zip(y, x), reverse=True))
print(sorted_x, sorted_y)
# ('a', 'c', 'e', 'd', 'b') (5, 4, 3, 2, 1)