# pythonic way to replace two character in a string

I have a string ,for example `s = "-1+2-3"` I want to replace all `-` to `+` and all `+` to `-`.

what I expected is `s = +1-2+3` .So I can’t just use `s.replace('-','+').replace('+','-')`,because it return `s=-1-2-3`,maybe a for loop can help. But I wonder if there is a pythonic way to do so?

thanks for all solutions i did a simple test for all function below

```def a(s="-1+2-3"):
s = re.sub('[+-]', lambda match: '-' if match[0] == '+' else '+', s)
return s

def b(s="-1+2-3"):
PLUS = '+'
MINUS = '-'
swap = {ord(PLUS): ord(MINUS), ord(MINUS): ord(PLUS)}
s = s.translate(swap)
return s

def c(s="-1+2-3"):
replacements = {"+": "-", "-": "+"}

return ''.join([replacements[i] if i in replacements.keys() else i for i in s])

def d(s="-1+2-3"):
return s.replace('+', 'x01').replace('-', '+').replace('x01', '-')

if __name__ == '__main__':
a = timeit.timeit(a, number=100000) # a=0.20307550000000002
b = timeit.timeit(b, number=100000) # b=0.08596850000000006
c = timeit.timeit(c, number=100000) # c=0.12203799999999998
d = timeit.timeit(d, number=100000) # d=0.033226100000000036
print(f"{a=}n{b=}n{c=}n{d=}n")
```

You can use translate (without `ord` as pointed out by Barmar):
```s = "-1+2-3"
```'+1-2+3'