Perform a list comprehension inside of a for loop in Python [closed]

In short what I need is to get for each element from this set uniqueFiles = {volcano_021, opencountry_test_017, opencountry_test_017} get the element of index 1 from each nested array in which the index 0 is equal to the element of uniqueFiles set which will be iterating.

For instance consider the followin list:

    arr = [['volcano_021', 'dusthaze-sky', 5, 1, 251, 55], 
           ['volcano_021', 'rocky-mountain', 11, 75, 249, 256],
           ['opencountry_test_017', 'overcast-sky', 5, 5, 252, 119], 
           ['opencountry_test_017', 'yellow-field', 4, 140, 254, 250],
           ['mountain_004', 'blue-sky', 9, 5, 246, 82]]

What I was trying to do is through a for loop get the following result for such a loop

'volcano_021' => ['dusthaze-sky','rocky-mountain']
'opencountry_test_017'=> ['overcast-sky', 'yellow-field']
'mountain_004' => ['blue-sky']

I came up with the following code…However it is not working.

I would like to do that using a list comprehension

  for file in uniqueFiles:
    print([n[1] for i,n in enumerate(arr) if n[i] == file])

Answer

You don’t need enumerate:

for file in uniqueFiles:
    print([n[1] for n in arr if n[0] == file])