Parse xsi:type=”” in Python using ElementTree

I know there are a few similar questions but none of the solutions seemed to work. I need to parse and XML file using python. I am using Elementree I am trying to print the value X. It is working as long as I am just looking for X-Values within EndPosition but I have to look for within all MoveToType. Is there someway to integrate that in Elementree. Thanks!

XML file:

<MiddleCommand xsi:type="MoveToType" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
        <CommandID>19828</CommandID>
        <MoveStraight>false</MoveStraight>
        <EndPosition>
            <Point>
                <X>528.65</X>
                <Y>33.8</Y>
                <Z>50.0</Z>
            </Point>
            <XAxis>
                <I>-0.7071067811865475</I>
                <J>-0.7071067811865477</J>
                <K>-0.0</K>
            </XAxis>
            <ZAxis>
                <I>0.0</I>
                <J>0.0</J>
                <K>-1.0</K>
            </ZAxis>
        </EndPosition>
    </MiddleCommand>

Python code:

import xml.etree.ElementTree as ET


#tree = ET.parse("102122.955_prog_14748500480769929136.xml")
tree = ET.parse("Move_to.xml")
root = tree.getroot()


for Point in root.findall("./EndPosition/Point/X"):
    print(Point.text)



for Point in root.findall('.//{MoveToType}/Endposition/Point/X'):
    print(Point.text)

Answer

Here is how you can get the wanted X value for MiddleCommand elements with xsi:type="MoveToType". Note that you need to use the full namespace URI inside curly braces when getting the value of the attribute.

import xml.etree.ElementTree as ET
 
tree = ET.parse("Move_to.xml")  # The real XML, with several MiddleCommand elements
    
for MC in tree.findall(".//MiddleCommand"):
    # Check xsi:type value and if it equals MoveToType, find the X value
    if MC.get("{http://www.w3.org/2001/XMLSchema-instance}type") == 'MoveToType':
        X = MC.find(".//X")
        print(X.text)