I have a function like given below. The code works fine and I require your assistance only in helping me to understand how the
return or function output is stored. I am a beginner and your inputs would be helpful
dataFramesDict = dict() def create_df(xls,s): ...... return sheet_df,sheet_name def transform_stage_1_df(sheet_df,sheet_name): ..... ..... return sheet_df,sheet_name def transform_stage_2_df(sheet_df, sheet_name): result = pd.concat(....) return result
As you can see, I am only returning the
result dataframe as output from the function. No other variables are returned from function
When I call the function in sequence like below, I expect it throw an error at the last line for
dataFramesDict[sheet_name] but it works fine.
sheet_df,sheet_name = create_df(xls,s) sheet_df,sheet_name = transform_stage_1_df(sheet_df,sheet_name) dataFramesDict[sheet_name] = transform_stage_2_df(sheet_df,sheet_name)
Shouldn’t I be getting an error message like below
sheet_name isn’t defined
I tried restarting the kernel to make sure that it’s not defined elsewhere.
sheet_name isn’t a global variable. It is only passed as an argument to the above function. Does function always return input arguments by default as well?
Variable sheet_name is defined outside transform_stage_2_df as you are using it as an input parameter and thus is already defined outside.
dataFramesDict[sheet_name] = transform_stage_2_df(sheet_df,sheet_name)