If the integer pointed to by num begins with or contains 3
please tell me how to code this
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Answer
You can try converting the number to a string and then check, like this
some_num = 34566 # str(some_num) return the number in string i.e returns '34566' if (len(str(some_num)) > 0 and ('3' in str(some_num)): print(True)