if number == 1:
print("One")
print("To exit type 'exit'.")
exit = raw_input()
if exit == "exit":
print("Welcome back.")
I am getting error on the if exit == “exit”: line… (Using python 2) The full error is : ‘unindent does not match any outer indentation level’
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Answer
Did you try like this:
def raw_input():
return "exit"
number = 1
if number == 1:
print("One")
print("To exit type 'exit'.")
exit = raw_input()
if exit == "exit":
print("Welcome back.")