if number == 1: print("One") print("To exit type 'exit'.") exit = raw_input() if exit == "exit": print("Welcome back.")
I am getting error on the if exit == “exit”: line… (Using python 2) The full error is : ‘unindent does not match any outer indentation level’
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Answer
Did you try like this:
def raw_input(): return "exit" number = 1 if number == 1: print("One") print("To exit type 'exit'.") exit = raw_input() if exit == "exit": print("Welcome back.")