Skip to content
Advertisement

How to query a nested tuple by index using a list to represent the index?

Get the value of a nested tuple at certain index like so:

tup = ((-3, (6, 15), 3), -9, ((-3, -6, 9, -5), -2))
    
print(tup[0][1][1])
>> 15

Want to query a nested tuple by index using as a list to represent the index, something like:

def getTupValue(input_tuple, input_list=[])
    ## returns the value at for example: tup[0][1][1]

getTupValue(tup, [0, 1, 1])
## returns 15

Advertisement

Answer

If you’re sure that there won’t be index errors, you can simply do:

def get_by_indexes(tup, indexes):
    for index in indexes:
        tup = tup[index]
    return tup


mytuple = ((-3, (6, 15), 3), -9, ((-3, -6, 9, -5), -2))
print(get_by_indexes(mytuple, [0, 1, 1]))

Output:

15
3 People found this is helpful
Advertisement