I have a html like:
<div class='mesage-in'> cool text here </div> <div class='mesage-in'> bad text here </div>
and my python code like:
texto = navegador.find_element_by_class_name('message-in').text
print(texto)
Is it possible make this get all elements with same class name and put on a array or define as different variable like this?
OutPut:
print(texto1) -> cool text here print(texto2) -> bad text here
#or
print(texto[0]) -> cool text here print(texto[1]) -> bad text here
Actualy my code only get the first one
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Answer
As per the HTML:
<div class='mesage-in'> cool text here </div> <div class='mesage-in'> bad text here </div>
The following line line of code:
texto = navegador.find_element_by_class_name('message-in').text
will always identify the first matching element, extract the text and assign it to texto. So when you try to print texto, the text of the very first element i.e. cool text here is printed.
Solution
You can get all elements with same classname i.e. mesage-in and put on a list as follows:
from selenium.webdriver.common.by import By texto = navegador.find_elements(By.CLASS_NAME, 'message-in')
Now you can print the desired texts with respect to their index as follows:
To print cool text here:
print(texto[0].text) # prints-> cool text here
To print bad text here:
print(texto[1].text) # prints-> bad text here
Outro
You can also crate a list of the texts using List Comprehension and print them as follows:
texto = [my_elem.text for my_elem in driver.find_elements(By.CLASS_NAME, "message-in")] print(texto[0]) # prints-> cool text here print(texto[1]) # prints-> bad text here