I want to find a link like https://stackoverflow.com/questions/37543724/python-regex-for-finding-all-words-in-a-string
in a big string but there are many links and I want all links that starts with https://stackoverflow.com/questions/
the string look like
something https://stackoverflow.com/questions/37543724/python-regex-for-finding-all-words-in-a-string
something
So my question is how can i find an uncompletet string?
Advertisement
Answer
Try this:
import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)b((?:https?://|wwwd{0,3}[.]|[a-z0-9.-]+[.][a-z]{2,4}/)(?:[^s()<>]+|(([^s()<>]+|(([^s()<>]+)))*))+(?:(([^s()<>]+|(([^s()<>]+)))*)|[^s`!()[]{};:'".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url if "stackoverflow.com/questions" in x[0]] # Driver Code string = 'content_license CC BY-SA 4.0 link https//stackoverflow.com/questions/26325943/many-threads-to-write-log-file-at-same-time-in-python title Many threads to writ' print(Find(string))
This outputs: ['stackoverflow.com/questions/26325943/many-threads-to-write-log-file-at-same-time-in-python']
, which is what I assume you want.