it is actually really difficult to write a suitable title for this question, so please correct if you find something more percise.
My problem is basically, that I have a txt file with a pattern which i want to sort.
Consider the following string
url1 cust1 number1 url2 cust2 number2 url3 cust3 number3 url4 cust4 number4
So all the lines are seperated and the pattern is the same. What i want to do now is to make 3 lists one for url one for cust and the last for number.
I have basically no idea how to do that as there is no pattern which I could search for with regex. So my idea was to do something like this:
for i in range(1, 3, len(txt)): l1.append(i)
And this i would do for all the 3 lists. Is there some other easier and more advanced solution?
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Answer
with open('path/to/input') as infile:
lines = (line.strip() for line in infile)
urls, custs, nums = zip(*zip(lines, lines, lines))
Output:
In [241]: urls
Out[241]: ('url1', 'url2', 'url3', 'url4')
In [242]: custs
Out[242]: ('cust1', 'cust2', 'cust3', 'cust4')
In [243]: nums
Out[243]: ('number1', 'number2', 'number3', 'number4')