I tried to find the line number of value which is 60 % of the maximum value in file.
if max_value=1 v_60 = 0.6
My file looks like this,
2.140672782874617625e-02 9.785932721712538307e-02 1.651376146788990640e-01 2.140672782874617763e-01 2.568807339449541427e-01 2.996941896024464813e-01 3.363914373088685017e-01 3.639143730886849615e-01 3.975535168195718505e-01 4.097859327217125425e-01 4.250764525993884213e-01 4.525993883792048256e-01 4.678899082568807044e-01 4.740061162079510226e-01 4.954128440366972197e-01 5.076452599388379117e-01 5.259938837920489219e-01 5.351681957186543714e-01 5.443425076452599320e-01 5.626911314984709422e-01 5.871559633027523262e-01 6.055045871559633364e-01 6.055045871559633364e-01 6.116207951070335991e-01 6.238532110091742355e-01 8.715596330275228176e-01 8.623853211009173680e-01 8.715596330275228176e-01 8.807339449541283782e-01 8.837920489296635651e-01 8.807339449541283782e-01 8.899082568807338278e-01 8.868501529051986410e-01 9.663608562691131665e-01 9.816513761467889898e-01 9.755351681957186161e-01 9.724770642201834292e-01 9.785932721712538029e-01 9.877675840978593635e-01 1.000000000000000000e+00 1.000000000000000000e+00
Now I print the line number of the max value by
l=numpy.where(file == np.amax(file))
now how to find the line number which has 0.60 just comparing up to two decimal value only in python.
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Answer
This will find the element closest to the 60% mark:
findit = data.max() * 0.6 print(np.argmin(np.abs((data-findit))))
Output:
21