Error handling for list comprehension in Python

Is there a way to handle errors in a python list comprehension. Preferably I would have something like this where the last two values are represented by None:

values = [try i ["row"] except KeyError None for i in [{"row" : 1}, {"Row" : 0}, {}]]

This throws a syntax error and the only way I can do it is:

values = []
for i in [{"row" : 1}, {"Row" : 0}, {}]:
    try: values.append (i ["row"])
    except KeyError: values.append (None)

I hope there is a more ‘neat’ way of doing this because the current solution is not preferable due to having to append to a blank list when a list comprehension does this in such a nice way!

Answer

you cannot catch an exception from a list comprehension (How can I handle exceptions in a list comprehension in Python?). But given what you want to do you could use get:

values = [i.get("row") for i in [{"row" : 1}, {"Row" : 0}, {}]]

if the key isn’t found in the dictionary get returns None, exactly what you’re looking for (it can return anything you want, just by passing the default value as second argument, see Why dict.get(key) instead of dict[key]?)