Django : transform a function download view into a class view

I am trying to rewrite a function view that download files into a classview. However I don’t see how to do it properly with the right methods, since I have an argument from the url. Then I do not which on of the class view I should be using.

I did an attemps that is worrking, but I do not see why it works with a get method. Anyone can explain me ?

Here is my function view that is working:

Function views.py:

def download(request, fileUUID):
    file = Documents.objects.get(Uuid=fileUUID)
    filename = file.Filename
    
    file_type, _ = mimetypes.guess_type(filename)
    url = file.Url
    blob_name = url.split("/")[-1]
    blob_content = AzureBlob().download_from_blob(blob_name=blob_name)

    if blob_content:
        response = HttpResponse(blob_content.readall(), content_type=file_type)
        response['Content-Disposition'] = f'attachment; filename={filename}'
        messages.success(request, f"{filename} was successfully downloaded")
        return response

    return Http404

urls.py:

from django.urls import path
from upload.views import *


urlpatterns = [ 
    path('upload/', DocumentUpload.as_view(), name="upload"),
    path('download/<str:fileUUID>/', DocumentDownload.as_view(), name="download"),
   ]

template file or html:

<a href="{% url 'download' file.Uuid %}">
       <i class='bx bxs-download'></i>
</a>

Answer

The path for download class based view:

 path('download/<str:fileUUID>/',views.DownloadView.as_view())

The view from the View:

class DownloadView(View):

    def get(self, request, *args, **kwargs):
        file = UploadFilesBlobStorage.objects.get(Uuid=self.kwargs['fileUUID'])
        filename = file.Filename
        file_type, _ = mimetypes.guess_type(filename)
        url = file.Url
        blob_name = url.split("/")[-1]
        blob_content = download_from_blob(blob_name)

        if blob_content:
            response = HttpResponse(blob_content.readall(), content_type=file_type)
            response['Content-Disposition'] = f'attachment; filename={filename}'
            messages.success(request, f"{filename} was successfully downloaded")
            return response

        return Http404