Reading URL image content from HTTPResponse in Python

I have an image URL in the form of a shareable Google Drive link that I would like to access in my Python script. Below is what I have been trying:

from PIL import Image
import requests

img = Image.open(requests.get(URL).raw)

However I know this returns an HTTPResponse. I have already consulted this and this thread to no avail. How do I get rid of all the other content in the URL and just keep the image?

Answer

Modification points:

• In your URL of https://drive.google.com/file/d/###fileId###/view?usp=sharing, this file is not publicly shared. When you want to use the URL of this file, please publicly share it.
• https://drive.google.com/file/d/###fileId###/view?usp=sharing of “webViewLink” is not the direct link. In this case, please use “webContentLink” like https://drive.google.com/uc?export=download&id=###fileId###".
• I think that it is required to modify requests.get(URL).raw of Image.open(requests.get(URL).raw) to BytesIO.

When these points are reflected in your script, it becomes as follows.

Modified script:

Please replace ###fileId### of https://drive.google.com/uc?export=download&id=###fileId### with your file ID.

from PIL import Image
import requests
import io

URL = "https://drive.google.com/uc?export=download&id=###fileId###"
img = Image.open(io.BytesIO(requests.get(URL).content))
print(img.format, img.size, img.mode)

• I could confirm that when the file of https://drive.google.com/uc?export=download&id=###fileId### is publicly shared, the script works.

Reference:

• Resource representations of Files