If I do this:
>>> False in [False, True] True
That returns True
. Simply because False
is in the list.
But if I do:
>>> not(True) in [False, True] False
That returns False
. Whereas not(True)
is equal to False
:
>>> not(True) False
Why?
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Answer
Operator precedence 2.x, 3.x. The precedence of not
is lower than that of in
. So it is equivalent to:
>>> not ((True) in [False, True]) False
This is what you want:
>>> (not True) in [False, True] True
As @Ben points out: It’s recommended to never write not(True)
, prefer not True
. The former makes it look like a function call, while not
is an operator, not a function.