I’m trying to figure out how to import a binary file into python, but it’s a lot of guesswork and trial and error. What I’d like to do in this case to is find where a specific date occurs in the bytestream, i.e:
import re import datetime import binascii import time with open('inputfile.nda', 'rb') as f: data = f.read() # This line needs fixing i = int.oppositeof_fromtimestamp(2019, 10, 10, 14, 53, 57.000) # '2019/10/10 14:53:57.000' time_stamp = i.to_bytes(4, byteorder='little') df = [m.start() for m in re.finditer(time_stamp, data)] print(df)
Is there a function (or set of functions) that can convert a date into a bytestream?
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Answer
You’re looking for datetime.timestamp()
:
import datetime ts = datetime.datetime(2019, 10, 10, 14, 53, 57) unix_time = int(ts.timestamp()) unix_time_bytes = unix_time.to_bytes(4, byteorder='little') print(ts, unix_time, unix_time_bytes)
outputs
2019-10-10 14:53:57 1570708437 b'xd5x1bx9f]'
Then you’ll probably want to use data.index(unix_time_bytes)
to look for the string, not regexps.