I’m working on a Flask app to return a zip file to a user of a directory (a bunch of photos) but I don’t want to include my server directory structure in the returned zip. Currently, I have this : This works great for creating and returning the zip but the file includes the structure of my server i.e. In
Tag: zip
How to access multiple CSV files that share the same name from multiple folders from a zip file
I have a zip file (stored locally) with multiple folders in it. In each folder are a few CSV files. I need to only access 1 particular CSV from each folder. The CSV’s I am trying to access from each folder all share the same name, but I cannot figure out how to access a particular file from each folder,
Python: How to pass output of the map function as arguments
I need to pass some arguments to the starmap_async function. I have a list my_list that has different values in it and some constants that are repeated. I have a way to pass the arguments as bellow: It works and generates arguments like this which is the desired output: Now I want to use the map function to do something
Creating a function that works like “zip”
I am trying to make a function that does something similar to “zip”. My problem is that the part doesn’t work. In the case below, it should take every third element from the L4, and append it to a new list, so I ended up with [[1, 4, 7], [2, 5, 8], [3, 6, 9]], but that is not really
ValueError: write() requires mode ‘w’, ‘x’, or ‘a’ in Python zipfile
I am trying to open a specific file in the archive and then write some content to it. I am using the zipfile.open() function to get access to the file: However, it gives me a warning about duplicate file called ‘hello.txt’. After that I get the following error: What am I doing wrong here? My full traceback: Answer Right now
How to temporarily re-name a file or Create a re-named temp-file in Python before zipping it
In the below code I am trying to zip a list list of files, I am trying to rename the files before zipping it. So the file name will be in a more readable format for the user. It works for the first time, but when I do it again It fails with the error the file name already exists
How to avoid subfolders creation while zipping files?
I am trying to zip the files from the list localpath_list in to one zip file `reports.zip. It works as expected, but when I extract the reports.zip file, there are folders created inside it. i.e all the .xls files are under files/sample/. what I need is just the .xls files without any folder structure. Answer According to: [Python.Docs]: zipfile –
Is there any method to compress ZIP files in python?
I have tried creating zip using zipfile and shutil. But, there was not visible file size compression in both the methods. zipfile shutil Is there any way to ensure file compression as well? Thanks. Answer You did zipfile.ZipFile docs state The compresslevel parameter controls the compression level to use when writing files to the archive. When using ZIP_STORED or ZIP_LZMA
Python associate function
I want to add the file extensions found in the function to the line of code where I specified “HERE”. In other words, not only “.txt”, but also the extensions of the above function should be brought that part. In short, I want to associate the following code with the function. Can you help me, with this? Answer Assuming that
How to label points in a scatter plot using zip and annotate
I am trying to use the zip and annotate in order to add labels in a vector tlab to a plot made using matplotlib. Instead, whilst trying to add the labels to the plot I get the error TypeError: unsupported format string passed to list.format How can I get the points on the plot using this method? code: In my