I have a text file that has a long 2D array as follows: The first element of each has numbers between 1 to 7. I want to read information of second element for all and find the maximum and minimum amount for each group between 1 to 7 separately. For example output like this: What is the most efficient way
Tag: min
Problems regarding “key” in the min() function
scores = {1:20, 2:40, 3:0, 4:25} min_score = min(scores, key=scores.get) I don’t quite understand the parameters that can be passed into the key. Running the above code gives me 3 which is what I wanted. scores.get return me a dict object at certain memory address. Calling scores.get() raised me an Error. key = scores complained that dict object is not
What functions can be used as ‘key=func’ arguments in the min() and max() functions?
For example: How do I know whether it is possible or not possible to use a function as a ‘key=func’ argument? Answer As indicated in the documentation, min() (and max()) expect a one-argument ordering function like that used for list.sort(). https://docs.python.org/3/library/functions.html#min So, what’s expected is a function that takes a single argument from the collection that min() or max() is
Find the nearest value to the given one in set
I am trying to find the closest number to 5 in set b. This is my code. Answer You can use the key argument to min to achieve this:
Getting the max and min from a dictionary without using max() and min()
I have a dictionary with two values (id and amount): and I want to find the id with the max and min amount from the dictionary without using the max and min functions. So desired output is: Answer You could just calculate it with a for loop: If your values are lists, you need to chose what index to use
Max and Min value for each colum of one Dataframe
Give this dataframe ‘x’: How I could get a list of pairs with the min and max of each column? The result would be: Answer You could define a function and call apply passing the function name, this will create a df with min and max as the index names: If you insist on a list of lists we can