I am using a deque to store data that is going to be processed. The processing only starts when the deque is full so in a first step I fill my buffer the following way: However, when I do this and I modify one of the elements of my_deque, all elements of my_deque are modified. One alternative I found to
Tag: deque
What is the difference between deque( [1,2,3] ) and deque.append( [1,2,3] )?
I have noticed that the following incurs an iterable error. But the code below works which I thought the same operation: What is the difference between the two ways above? Thanks for your help in advance. Answer q.popleft() returns the first element of the deque. In the first case it is int and in the second it is a list
delete the hashed node in deque in O(1)
How do I hash a built-in node in deque (which is a double linked list) and delete the node in the middle in O(1)? Is the built-in node exposed? For example, I want to save a deque’s node in dict so I can delete the node in constant time later. This is a use case in LRU, using deque so