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Regex to extract usernames/names from a string

Tomerikoo
Zaibi

I have strings that includes names and sometime a username in a string followed by a datetime stamp:

GN1RLWFH0546-2020-04-10-18-09-52-563945.txt
JOHN-DOE-2020-04-10-18-09-52-563946t64.txt
DESKTOP-OHK45JO-2020-04-09-02-27-11-451975.txt

I want to extract the usernames from this string:

GN1RLWFH0546
JOHN-DOE   
DESKTOP-OHK45JO

I have tried different regex patterns the closest I came to extract was following:

GN1RLWFH0546
DESKTOP
JOHN

Using the following regex pattern:

names = re.search(r"(?([0-9A-Za-z]+))?", agent_str)
print(names.group(1))

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Answer

You may get all text up to the first occurrence of -+digits+-:

^.*?(?=-d+-)

If the number must be exactly 4 digits (say, if it is a year), then replace + with {4}:

^.*?(?=-d{4}-)

See the regex demo

Details

  • ^ – start of string
  • .*? – any 0+ chars other than line break chars, as few as possible
  • (?=-d+-) – up to the first occurrence of - and 1+ digits (or, if d{4} is used, exactly four digits) and then - (this part is not added to the match value as the positive lookahead is a non-consuming pattern).

See Python demo:

import re
strs = ["GN1RLWFH0546-2020-04-10-18-09-52-563945.txt", "JOHN-DOE-2020-04-10-18-09-52-563946t64.txt", "DESKTOP-OHK45JO-2020-04-09-02-27-11-451975.txt"]
rx = re.compile(r"^.*?(?=-d+-)")
for s in strs:
  m = rx.search(s)
  if m:
    print("{} => '{}'".format(s, m.group()))

Output:

GN1RLWFH0546-2020-04-10-18-09-52-563945.txt => 'GN1RLWFH0546'
JOHN-DOE-2020-04-10-18-09-52-563946t64.txt => 'JOHN-DOE'
DESKTOP-OHK45JO-2020-04-09-02-27-11-451975.txt => 'DESKTOP-OHK45JO'