Python – Solve some mathematical problems in a list filled with random elements [closed]

Task: In a list filled with random numbers you need to count:

1. A sum of negative numbers
2. A sum of even numbers
3. A sum of odd numbers
4. A product of elements with indexes that multiple 3
5. A product of elements between min and max element
6. A sum of elements, which located between first and last element

I can’t figure out how to solve last two issues

The code I have so far:

import random

size = int(input('Enter the size of a list: '))
begin = int(input('Enter the beginning of a list: '))
end = int(input('Enter the end of a list: '))

my_list = list()
for i in range(size):
    my_list.append(random.randint(begin, end))

for i in range(0, len(my_list)):
    print(f'{my_list[i]}[{i}]', end=' ')
print()

mul = 1
for i in range(0, len(my_list), 3):
    print(f'{mul} * {my_list[i]}[{i}] = ', end=' ')
    mul *= my_list[i]
    print(mul)

sum_list = [0] * 3

for item in my_list:
    if item < 0:
        sum_list[0] += item
    if item % 2 == 0:
        sum_list[1] += item
    if item % 2 != 0:
        sum_list[2] += item

print(f'Sum negative: {sum_list[0]}')
print(f'Sum even: {sum_list[1]}')
print(f'Sum odd: {sum_list[2]}')
print(f'Mul even 3 index: {mul}')

Answer

A product of elements between min and max element

For this task, you can use .sort() method of the “list” object to sort it in-place then use list indexes to exclude the first and last item (min and max because it is sorted) and then use math.prod to calculate the product of rest

import math
my_list.sort()
math.prod(my_list[1:-1]) if len(my_list) > 2 else 0

A sum of elements, which located between the first and last element

Use list indexes to get the remaining elements and sum() them

sum(my_list[1:-1]) if len(my_list) > 2 else 0 # we need to check if list is long enough