I am trying to emulate a circumstance where i send information and only get a true or false as a return. So i can check each character and if it is true, that means that character is in the string. I would know there would be a position 0 to some number x. I would receive a true result and eventually only receive false result and then I would know the string has been solved. In my circumstance i would not know the target string.
I am trying to iterate through all characters and see if it matches the string character. if it does, I add the character to a list until the list contains all the characters of the string. but for some reason, this isn’t working.
import string
hi = list()
swoll = "dkjfksjdfksjdkfjksdjfsjkdfjsjreuvnslei"
characters = string.ascii_lowercase + string.ascii_uppercase + string.digits
for ch in characters:
print(''.join(hi) + ch)
for i in swoll:
if i == ch:
hi.append(ch)
print(''.join(hi))
break
else:
continue
results:
a b c d d de de def def defg defh defi defi defij defij defijk defijk defijkl defijkl defijklm defijkln defijkln defijklno defijklnp defijklnq defijklnr defijklnr defijklnrs defijklnrs defijklnrst defijklnrsu defijklnrsu defijklnrsuv defijklnrsuv defijklnrsuvw defijklnrsuvx defijklnrsuvy defijklnrsuvz defijklnrsuvA defijklnrsuvB defijklnrsuvC defijklnrsuvD defijklnrsuvE defijklnrsuvF defijklnrsuvG defijklnrsuvH defijklnrsuvI defijklnrsuvJ defijklnrsuvK defijklnrsuvL defijklnrsuvM`
As you can see, it does not match the string
When I tried the code above, I was expecting the string to come out the same as the other string.
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Answer
Based on my understanding of the question, I’ve implemented a function which I believe emulates the interface you are talking to:
spos = 0
def in_swoll(ch):
global spos
if spos == len(swoll) or ch != swoll[spos]:
return False
spos += 1
return True
This will return True and increment the counter into swoll when a character matches, otherwise it will return False.
You can then use this function in a loop which iterates until False is returned for all characters in characters. Inside the loop characters is iterated until a match is found, at which point it is added to hi:
hi = []
while True:
for ch in characters:
if in_swoll(ch):
hi.append(ch)
print(''.join(hi))
break
else:
# no matches, we're done
break
Output for your sample data:
d dk dkj dkjf dkjfk dkjfks dkjfksj dkjfksjd dkjfksjdf dkjfksjdfk dkjfksjdfks dkjfksjdfksj dkjfksjdfksjd dkjfksjdfksjdk dkjfksjdfksjdkf dkjfksjdfksjdkfj dkjfksjdfksjdkfjk dkjfksjdfksjdkfjks dkjfksjdfksjdkfjksd dkjfksjdfksjdkfjksdj dkjfksjdfksjdkfjksdjf dkjfksjdfksjdkfjksdjfs dkjfksjdfksjdkfjksdjfsj dkjfksjdfksjdkfjksdjfsjk dkjfksjdfksjdkfjksdjfsjkd dkjfksjdfksjdkfjksdjfsjkdf dkjfksjdfksjdkfjksdjfsjkdfj dkjfksjdfksjdkfjksdjfsjkdfjs dkjfksjdfksjdkfjksdjfsjkdfjsj dkjfksjdfksjdkfjksdjfsjkdfjsjr dkjfksjdfksjdkfjksdjfsjkdfjsjre dkjfksjdfksjdkfjksdjfsjkdfjsjreu dkjfksjdfksjdkfjksdjfsjkdfjsjreuv dkjfksjdfksjdkfjksdjfsjkdfjsjreuvn dkjfksjdfksjdkfjksdjfsjkdfjsjreuvns dkjfksjdfksjdkfjksdjfsjkdfjsjreuvnsl dkjfksjdfksjdkfjksdjfsjkdfjsjreuvnsle dkjfksjdfksjdkfjksdjfsjkdfjsjreuvnslei